s^-3(s+2)=4

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Solution for s^-3(s+2)=4 equation: 



s^-3(s+2)=4

We move all terms to the left:

s^-3(s+2)-(4)=0

We add all the numbers together, and all the variables

s-3(s+2)-4=0

We multiply parentheses

s-3s-6-4=0

We add all the numbers together, and all the variables

-2s-10=0

We move all terms containing s to the left, all other terms to the right

-2s=10

s=10/-2

s=-5

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